Share the simplest way to write a conditional judgment statement in python

This article mainly introduces Python Tips for returning true or false values ​​(True or False). This article discusses the simplest condition Judgment statement writing method. This article gives For two concise writing methods, friends who need it can refer to the following code:

def isLen(strString):
    if len(strString)>6:
        return True
    else:
        return False

Maybe you have discovered that in Python 3, there is actually a way to complete it in just one line

: The code is as follows:

>>> def isLen(strString):
       return True if len(strString)>6 else False

But. . . Could it be simpler?

How to use Python to express conditional statements more easily, just

fun :)One way is to use a list

: The code is as follows:

>>> def isLen(strString):
       #这里注意false和true的位置， 多谢网友@小王的指正
       return [False,True][len(strString)>6]

The principle is very simple. The Boolean value True is evaluated as 1 by index, and False is equal to 0. Can it be simpler?

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