Understanding the super function in Python

The super() function has the following specific functions based on the two parameters passed in:

The class name passed in as the first parameter determines the current position in the MRO. MRO (Method Resolution Order);

Determine the current MRO list through self passed in as the second parameter.

def super(cls, inst):
    mro = inst.__class__.mro() #确定当前MRO列表
    return mro[mro.index(cls) + 1] #返回下一个类

The following code:

class A(object):
  def name(self):
    print('name is xiaoming')    #super(A,self).name()class B(object):
  def name(self):
    print('name is cat')class C(A,B):
  def name(self):
    print('name is wang')
    super(C,self).name()if __name__ == '__main__':
  c = C()
  print(c.__class__.__mro__)
  c.name()

Execute the above code output: When the super() function under class C is executed, the name function under class A is actually called. The super() function is commented out in A, so execution does not continue backwards. And the current MRO list order is printed out as C,A,B,object.

(<class &#39;__main__.C&#39;>, <class &#39;__main__.A&#39;>, <class &#39;__main__.B&#39;>, <class &#39;object&#39;>)name is wang
name is xiaoming

When we remove the comments in class A, the execution code output: You can see that when A is executed, execution continues The name() function in B. If there is still a super function in B, it will continue to look up to see if there is a name() function in object.

(<class &#39;__main__.C&#39;>, <class &#39;__main__.A&#39;>, <class &#39;__main__.B&#39;>, <class &#39;object&#39;>)name is wang
name is xiaoming
name is cat

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