Home > Backend Development > PHP Tutorial > PHP session application example login verification

PHP session application example login verification

黄舟
Release: 2023-03-03 18:58:02
Original
889 people have browsed it

 
 
Login 
 

 
 
 
 
 
 
 
 
 
 
 
 
 



用户名:
密码:
Cookie保存时间:









------------------------------------------------- -----------------------

@mysql_connect("localhost", "root","1981427") //Required before selecting the database Connect to the database server first
or die("Database server connection failed");
@mysql_select_db("test") //Select database mydb
or die("Database does not exist or is unavailable");
//Get user input
$username = $_POST['username'];
$passcode = $_POST['passcode'];
//Execute SQL statement to obtain the value of Session
$query = @mysql_query("select username, userflag from users "
. "where username = '$username' and passcode = '$passcode'")
or die("SQL statement execution failed");
//Determine whether the user exists and whether the password is correct
if($row = mysql_fetch_array($query ))
{
session_start(); //Mark the start of Session
//Determine whether the user's permission information is valid, if it is 1 or 0, it means it is valid
if($row['userflag'] == 1 or $row ['userflag'] == 0)
{
$_SESSION['username'] = $row['username'];
$_SESSION['userflag'] = $row['userflag'];
echo "< a href="http://www.php1.cn/"> }
else //If the permission information is invalid, output an error message
{
echo "User permission information is incorrect";
}
}
else //If If the username and password are incorrect, the output error
{
echo "Username or password is incorrect";
}
?>

------------------------ ----------------------------------------
unset($ _SESSION['username']);
unset($_SESSION['passcode']);
unset($_SESSION['userflag']);
echo "Logout successful";
?>

----- -------------------------------------------------- --------

session_start();
if(isset($_SESSION['username']))
{
@mysql_connect("localhost", "root","1981427" ) //You need to connect to the database server before selecting the database
or die("Database server connection failed");
@mysql_select_db("test") //Select the database mydb
or die("The database does not exist or is unavailable");
//Get Session
$username = $_SESSION['username'];
//Execute SQL statement to get the value of userflag
$query = @mysql_query("select userflag from users "
."where username = '$username' ")
or die("SQL statement execution failed");
$row = mysql_fetch_array($query);
//Compare the permission information in the current database with the information in the Session, and update the Session information if they are different
if ($row['userflag'] != $_SESSION['userflag'])
{
$_SESSION['userflag'] = $row['userflag'];
}
//Output different welcomes according to the value of Session Information
if($_SESSION['userflag'] == 1)
echo "Welcome administrator".$_SESSION['username']."Log in to the system";
if($_SESSION['userflag'] == 0)
echo "Welcome user".$_SESSION['username']."Log in to the system";
echo " }
else
{
echo " You do not have permission to access this page";
}
?> Beginner to PHP. I also reprinted it from others. I haven't tested it on the computer yet. I will collect it first.

From: http://phpstart.php100.com/apps-htm-q -diary-a-detail-did-7373.html

The above is the content of php session application instance login verification. For more related content, please pay attention to the PHP Chinese website (m.sbmmt.com)!


source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template