PHP returns json PHP method to determine whether a json object exists

WBOY
Release: 2016-07-28 08:27:53
Original
1453 people have browsed it

In the actual test, when PHP reads the json array and uses simple if or array_key_exists to determine whether the object exists, an error will be reported. The following is the correct judgment method from Google search

In fact, the error is reported because I am not very proficient in PHP. Maybe the correct judgment method I think is not the most perfect solution or even wrong. This blog post is reserved for my own use. Error code:

<span>$structure</span> = <span>imap_fetchstructure</span>(<span>$connection</span>, <span>$id</span>,<span> FT_UID);
</span><span>if</span> (<span>array_key_exists</span>('parts', <span>$structure</span><span>))
{
}</span>
Copy after login

An error will appear Warning: array_key_exists() expects parameter 2 to be array, boolean Given

The correct solution is:

<span>if</span> (<span>is_array</span>(<span>$structure</span>) && <span>array_key_exists</span>('parts', <span>$structure</span>)) <br>{ <span>//</span><span>...magic stuff here <br>}</span>
Copy after login

And another way is to use isset to directly judge:

<span>if</span>(<span>isset</span>(<span>$structure</span>['parts'<span>]))
 {
 }<br></span>
Copy after login
   //This function is used to test whether the variable has been configured. Returns true if the variable already exists. Otherwise a false value is returned.

  // Therefore, it is necessary to return TURE

only if the variable exists and the value is not NULL

The above introduces the method for PHP to return json and PHP to determine whether a json object exists, including the content of PHP returning json. I hope it will be helpful to friends who are interested in PHP tutorials.

Related labels:
source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template
About us Disclaimer Sitemap
php.cn:Public welfare online PHP training,Help PHP learners grow quickly!