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请用json_decode解析成数组

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Release: 2016-06-20 12:45:06
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jsonp107({"SM_368_dsr-1097280647":{v:0,nv:100,m_UFB:0,m:4.89661,m_g:20.15,s_UFB:0,s:4.8744,s_g:31.49,c_UFB:0,c:4.87867,c_g:39.55,gp:100.00,ss:290167,hdr:true},"ICCP_1_522177046867":4915});


我要取4915这个值,请用json_decode解析成数组来取值。

求这几行代码


回复讨论(解决方案)

http://bbs.csdn.net/topics/391853070?page=1#post-400534281
我给你答了 虽然有点蠢 但是勉强算是你要的效果吧。

或者等待大神给你来答

$s =<<< TXTjsonp107({"SM_368_dsr-1097280647":{v:0,nv:100,m_UFB:0,m:4.89661,m_g:20.15,s_UFB:0,s:4.8744,s_g:31.49,c_UFB:0,c:4.87867,c_g:39.55,gp:100.00,ss:290167,hdr:true},"ICCP_1_522177046867":4915});TXT;$s = preg_replace_callback('/[-".\w]+/',   function($m) { return '"' . trim($m[0],'"') . '"'; },   preg_replace('/^.+\((.+)\).+$/', '$1', $s));print_r(json_decode($s, 1));
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Array(    [SM_368_dsr-1097280647] => Array        (            [v] => 0            [nv] => 100            [m_UFB] => 0            [m] => 4.89661            [m_g] => 20.15            [s_UFB] => 0            [s] => 4.8744            [s_g] => 31.49            [c_UFB] => 0            [c] => 4.87867            [c_g] => 39.55            [gp] => 100.00            [ss] => 290167            [hdr] => true        )    [ICCP_1_522177046867] => 4915)
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楼主SB.不要说是学PHP的。真他妈丢人

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