Query statement:
The following query attempts to use the CASE statement in the WHERE clause to filter based on the values of @locationType and @locationID:
<code class="language-sql">declare @locationType varchar(50); declare @locationID int; SELECT column1, column2 FROM viewWhatever WHERE CASE @locationType WHEN 'location' THEN account_location = @locationID WHEN 'area' THEN xxx_location_area = @locationID WHEN 'division' THEN xxx_location_division = @locationID END;</code>
Error:
This query results in a syntax error because the CASE expression expects a single return value. Various WHEN clauses incorrectly included an equality comparison (= @locationID) that was not a CASE expression.
Solution:
The correct syntax for using a CASE statement in a WHERE clause is to assign the expression to the target column:
<code class="language-sql">declare @locationType varchar(50); declare @locationID int; SELECT column1, column2 FROM viewWhatever WHERE @locationID = CASE @locationType WHEN 'location' THEN account_location WHEN 'area' THEN xxx_location_area WHEN 'division' THEN xxx_location_division END;</code>
In this modified query, the CASE expression returns the corresponding location identifier based on the value of @locationType. The WHERE clause then compares this value with @locationID to filter the results as expected.
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