How to Efficiently Replace All Character Occurrences in a C String?

Replacing All Character Occurrences in a String

Question:

How can I efficiently replace all occurrences of a specific character with another character in a std::string in C ?

Answer:

While std::string does not provide a built-in function for this, you can utilize the stand-alone replace function from the algorithm header. Here's how:

#include <algorithm>
#include <string>

void replace_characters(std::string& s, char old_char, char new_char) {
  std::replace(s.begin(), s.end(), old_char, new_char); // replace all old_char with new_char in s
}

Example:

int main() {
  std::string s = "example string";
  replace_characters(s, 'x', 'y'); // replace all 'x' with 'y'
  std::cout << s << std::endl; // Output: "example string" with 'x' replaced by 'y'
  return 0;
}

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