How Can We Efficiently Check if a String is a Palindrome?

Refined Palindrome Checker

In this demonstration, we delve into the intricacies of checking whether a given string is a palindrome. A palindrome exhibits the remarkable property of being read identically both forward and backward. One common approach involves converting the string into a char array and comparing each character at opposite ends of the array.

However, there is a more efficient and succinct solution:

public static boolean isPalindrome(char[] word) {
    int i1 = 0;
    int i2 = word.length - 1;
    while (i2 > i1) {
        if (word[i1] != word[i2]) {
            return false;
        }
        ++i1;
        --i2;
    }
    return true;
}

This enhanced method incorporates a while loop that iterates from the beginning and end of the word, comparing each character along the way. If any pair of characters does not match, the string is not a palindrome. By incrementing i1 and decrementing i2 until they meet in the middle of the word, we can efficiently check for palindromes.

Example:

Consider the input string "andna":

• i1 = 0, i2 = 4

• Compare word[0] (a) with word[4] (a): Equal

  • i1 = 1, i2 = 3

• Compare word[1] (n) with word[3] (n): Equal

  • i1 = 2, i2 = 2
• i1 and i2 are now equal, so the loop terminates and returns true.

This optimized algorithm provides a streamlined method to determine whether a given string is a palindrome.

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