Removing punctuation from strings is a common task in many programming scenarios. While various methods exist, selecting the most efficient one can be challenging.
For maximum efficiency, string translation reigns supreme. Using s.translate(None, string.punctuation) ensures raw string operations are performed in C, providing unmatched speed. For Python versions 3.9 and above, leverage s.translate(str.maketrans('', '', string.punctuation)).
If speed is not paramount, consider these alternatives:
To gauge the performance of these methods, the following code was executed:
import re, string, timeit s = "string. With. Punctuation" exclude = set(string.punctuation) table = string.maketrans("","") regex = re.compile('[%s]' % re.escape(string.punctuation)) def test_set(s): return ''.join(ch for ch in s if ch not in exclude) def test_re(s): return regex.sub('', s) def test_trans(s): return s.translate(table, string.punctuation) def test_repl(s): for c in string.punctuation: s=s.replace(c,"") return s print "sets :",timeit.Timer('f(s)', 'from __main__ import s,test_set as f').timeit(1000000) print "regex :",timeit.Timer('f(s)', 'from __main__ import s,test_re as f').timeit(1000000) print "translate :",timeit.Timer('f(s)', 'from __main__ import s,test_trans as f').timeit(1000000) print "replace :",timeit.Timer('f(s)', 'from __main__ import s,test_repl as f').timeit(1000000)
The results revealed the following:
When optimizing for speed, string translation is the undisputed choice. For less performance-intensive scenarios, alternative approaches like set exclusion or regular expressions can provide satisfactory results.
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