How Can I Efficiently Parse Command-Line Arguments in Java?-javaTutorial-php.cn

How Can I Efficiently Parse Command-Line Arguments in Java?

Susan Sarandon

Release： 2024-12-19 19:24:16

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How Can I Efficiently Parse Command-Line Arguments in Java?

How do I Parse Command Line Arguments in Java?

To efficiently parse command line arguments in Java, consider leveraging one of the following libraries:

Apache Commons CLI: http://commons.apache.org/cli/
JSAP (Java Simple Argument Parser): http://www.martiansoftware.com/jsap/

Java also provides the Scanner class for manual argument parsing: http://docs.oracle.com/javase/7/docs/api/java/util/Scanner.html

Example using Commons CLI:

To parse two string arguments using Commons CLI, create a CommandLineParser and parse the arguments using .parse(...).

import org.apache.commons.cli.*;

public class Main {

    public static void main(String[] args) throws Exception {
        // Create options
        Options options = new Options();
        options.addOption("i", "input", true, "input file path");
        options.getOption("i").setRequired(true);
        options.addOption("o", "output", true, "output file");
        options.getOption("o").setRequired(true);

        // Parse arguments
        CommandLineParser parser = new DefaultParser();
        CommandLine cmd = parser.parse(options, args);

        // Get parsed values
        String inputFilePath = cmd.getOptionValue("input");
        String outputFilePath = cmd.getOptionValue("output");

        System.out.println(inputFilePath);
        System.out.println(outputFilePath);
    }
}

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Usage from command line:

$> java -jar target/my-utility.jar -i asd

Missing required option: o

usage: utility-name
 -i,--input <arg>    input file path
 -o,--output <arg>   output file

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