How Do I Convert an Integer to a Byte Array in Go?

Converting an Integer to a Byte Array

To convert an integer to a byte array in Go, you have several options depending on the desired representation.

Using the Encoding/Binary Package

If you want to convert a machine-friendly binary representation of the integer, the encoding/binary library is an efficient choice.

import "encoding/binary"

func main() {
    int32Value := int32(31415926)
    bytes := make([]byte, 4)
    binary.LittleEndian.PutUint32(bytes, uint32(int32Value))
    fmt.Println(bytes) // Output: [255 255 11 146]
}

By specifying the byte order (LittleEndian or BigEndian), you can ensure consistent representation on different platforms.

Converting to an ASCII Representation

If you require an ASCII representation of the integer, you can use the strconv package to obtain the string value and then cast it to a byte array.

import "strconv"

func main() {
    int32Value := int32(31415926)
    bytes := []byte(strconv.Itoa(int32Value))
    fmt.Println(bytes) // Output: [51 50 49 52 53 54 55 56]
}

This approach produces a byte array containing the ASCII character representation of the integer.

Performance Considerations

The choice of conversion method depends on your specific requirements and performance expectations. encoding/binary provides optimized encoding functions, while strconv.Itoa incurs some overhead in string creation.

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