Home > Web Front-end > JS Tutorial > How to Pass a Complete Model via FormData to an ASP.NET MVC Controller?

How to Pass a Complete Model via FormData to an ASP.NET MVC Controller?

Susan Sarandon
Release: 2024-12-19 14:31:10
Original
609 people have browsed it

How to Pass a Complete Model via FormData to an ASP.NET MVC Controller?

Passing a Whole Model through FormData and Receiving It in MVC

In ASP.NET MVC, it is often desirable to pass a complete model object through a form to the controller. However, simply appending the model to FormData will result in it being received as a string in the controller, rendering it unusable.

Solution:

To effectively pass a model through FormData, the following approach can be adopted:

  1. Serialize the Model:
    Utilize jQuery's FormData function to serialize the model. This will convert the model into a FormData object, which can include both model properties and file inputs:

    var formdata = new FormData($('form').get(0));
    Copy after login
  2. Post the FormData:
    Send the FormData object via an AJAX POST request:

    $.ajax({
      url: '@Url.Action("YourActionName", "YourControllerName")',
      type: 'POST',
      data: formdata,
      processData: false,
      contentType: false,  
    });
    Copy after login
  3. Receive the Model in the Controller:
    In the controller action, accept the model as a parameter of the appropriate type:

    [HttpPost]
    public ActionResult YourActionName(YourModelType model)
    {
    }
    Copy after login
  4. Optional: Handling Additional Properties:
    If the model does not contain properties for additional form data, you can append them manually:

    formdata.append('someProperty', 'SomeValue');
    Copy after login

By following these steps, you can effectively pass a model through FormData and receive it in your MVC controller in a usable format.

The above is the detailed content of How to Pass a Complete Model via FormData to an ASP.NET MVC Controller?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template