Retrieving and Displaying Images from MySQL in an HTML Tag
Question:
You have created a MySQL database and a table with a BLOB column to store JPEG files. While attempting to retrieve the image data into an HTML tag, you're encountering issues with the PHP variable $result. How can you incorporate $result into the HTML to display the image?
Answer:
It is not possible to directly include the $result variable in the HTML tag. The $result variable contains the raw image data retrieved from the database. To display the image, you need to create a separate PHP script that will output the image data.
Solution:
Modify catalog.php:
Change the HTML tag to refer to a new PHP script that will retrieve and output the image data:
<img src="getImage.php?id=1" width="175" height="200" />
Create getImage.php:
Create a new PHP script named getImage.php that performs the following tasks:
<?php // Establish database connection $link = mysqli_connect("localhost", "root", "", "dvddb"); // Prepare SQL statement $sql = "SELECT dvdimage FROM dvd WHERE>
This script establishes a database connection, executes the SQL statement to retrieve the image data for the specified ID, sets the image content type header, and outputs the image data.
Explanation:
By creating a separate script to retrieve and output the image data, you can separate the database operations from the HTML display. This approach ensures that your HTML code remains clean and organized.
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