How Can We Optimize a Palindrome Check String Algorithm?

How to Enhance Palindrome Check String Algorithm

The provided code compares each character of a word to its corresponding character from the end, effectively checking for palindromes. While this approach is functional, there are optimizations that can improve its efficiency.

A better solution involves using two pointers that move towards each other from the beginning and end of the word. The following modified code addresses this:

public static boolean istPalindrom(char[] word){
    int i1 = 0;
    int i2 = word.length - 1;
    while (i2 > i1) {
        if (word[i1] != word[i2]) {
            return false;
        }
        ++i1;
        --i2;
    }
    return true;
}

Example:

Consider the word "andna."

• i1 is initialized to 0, and i2 is initialized to 4 (length - 1).
• In the first loop iteration, word[0] and word[4] are compared. Since they're equal, i1 is incremented to 1, and i2 is decremented to 3.
• The process continues until i1 and i2 cross at the center of the word, indicating a palindrome.

This modification enhances code efficiency by eliminating the loop condition that checks for even or odd word length, making it more concise and performant.

The above is the detailed content of How Can We Optimize a Palindrome Check String Algorithm?. For more information, please follow other related articles on the PHP Chinese website!