How Can Goroutines and Channels Efficiently Compare the Values of Two Binary Trees in Go?

Equivalent Binary Trees in Go Tour

This exercise involves determining whether two binary trees contain the same values. In your implementation, you rightly use goroutines to concurrently traverse both trees and send their values to channels. However, the issue arises when trying to signal that there are no more elements left in the trees.

Avoiding Premature Closure

Using close(ch) on Walk would prematurely close the channels before all values are sent, as recursion would exit early. Instead, an elegant solution involves using a closure:

func Walk(t *tree.Tree, ch chan int) {
    defer close(ch) // Closes the channel when this function returns
    
    var walk func(t *tree.Tree)
    walk = func(t *tree.Tree) {
        if t == nil {
            return
        }
        
        walk(t.Left)
        ch <- t.Value
        walk(t.Right)
    }
    
    walk(t)
}

This closure captures the ch channel and ensures that it's only closed when there are no more nodes to traverse. The defer close statement ensures that the closure runs after all recursive calls have completed.

With this fix, your Same function can accurately determine equivalence by iteratively receiving values from the channels and comparing them.

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