Home > Web Front-end > JS Tutorial > LeetCode Meditations: Merge Intervals

LeetCode Meditations: Merge Intervals

Linda Hamilton
Release: 2024-12-14 16:24:10
Original
750 people have browsed it

LeetCode Meditations: Merge Intervals

Let's start with the description for Merge Intervals:

Given an array of intervals where intervals[i] = [start_i, end_i], merge all overlapping intervals, and return an array of the non-overlapping intervals that cover all the intervals in the input.

For example:

Input: intervals = [[1, 3], [2, 6], [8, 10], [15, 18]]
Output: [[1, 6], [8, 10], [15, 18]]

Explanation: Since intervals [1, 3] and [2, 6] overlap, merge them into [1, 6].
Copy after login
Copy after login

Or:

Input: intervals = [[1, 4], [4, 5]]
Output: [[1, 5]]

Explanation: Intervals [1, 4] and [4, 5] are considered overlapping. 
Copy after login
Copy after login

We can start by sorting the intervals first, so that we can compare them easily later:

intervals.sort((a, b) => a[0] - b[0]);
Copy after login
Copy after login

Also, we can initialize a result array which initially holds the first element of the newly sorted intervals:

let result = [intervals[0]];
Copy after login

We need to track the last merged interval's end to compare it with the start of the current interval we are looking at to check if they overlap.

Note
For two intervals not to overlap, the
Note
For two intervals not to overlap, the start of one should be strictly larger than the end of the other or the end of the one should be strictly smaller than the start of the other, as mentioned in our chapter introduction.
start of one should be strictly larger than the end of the other
or the end of the one should be strictly smaller than the start of the other, as mentioned in our chapter introduction.

If they don't overlap, we can just add that interval to result. Otherwise, we need to update the "last end," effectively merging the intervals:

Input: intervals = [[1, 3], [2, 6], [8, 10], [15, 18]]
Output: [[1, 6], [8, 10], [15, 18]]

Explanation: Since intervals [1, 3] and [2, 6] overlap, merge them into [1, 6].
Copy after login
Copy after login

And, the only thing left to do is to return the result:

Input: intervals = [[1, 4], [4, 5]]
Output: [[1, 5]]

Explanation: Intervals [1, 4] and [4, 5] are considered overlapping. 
Copy after login
Copy after login

And, this is how our final solution looks like in TypeScript:

intervals.sort((a, b) => a[0] - b[0]);
Copy after login
Copy after login

Time and space complexity

We are sorting intervals, and the built-in sort function has O(n log n)O(n log n) O(n log n) time complexity. (The looping is O(n)O(n) O(n) , but the overall time complexity is O(n log n)O(n log n) O(n log n) ).

The result array can increase in size as the size of the input array intervals increases, therefore we have O(n)O(n) O(n) space complexity.


Next up, we'll take a look at the last problem in the chapter, Non-overlapping Intervals. Until then, happy coding.

The above is the detailed content of LeetCode Meditations: Merge Intervals. For more information, please follow other related articles on the PHP Chinese website!

source:dev.to
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template