Home > Web Front-end > JS Tutorial > How Can I Detect Firefox Versions 3 or 4 Using JavaScript?

How Can I Detect Firefox Versions 3 or 4 Using JavaScript?

DDD
Release: 2024-12-14 12:16:16
Original
241 people have browsed it

How Can I Detect Firefox Versions 3 or 4 Using JavaScript?

Browser Version Detection

Problem:
How can you determine the version of a visitor's browser in JavaScript, specifically for Firefox versions 3 or 4?

Solution:

To detect a browser's version, rather than just its type, you can utilize JavaScript's navigator.userAgent property. This property contains a string with information about the browser, including the version number.

The following code snippet exemplifies a function that analyzes the navigator.userAgent string and extracts the browser version:

navigator.sayswho = (function () {
  var ua = navigator.userAgent;
  var tem;
  var M = ua.match(/(opera|chrome|safari|firefox|msie|trident(?=\/))\/?\s*(\d+)/i) || [];
  if (/trident/i.test(M[1])) {
    tem = /\brv[ :]+(\d+)/g.exec(ua) || [];
    return 'IE ' + (tem[1] || '');
  }
  if (M[1] === 'Chrome') {
    tem = ua.match(/\b(OPR|Edge)\/(\d+)/);
    if (tem != null) return tem.slice(1).join(' ').replace('OPR', 'Opera');
  }
  M = M[2] ? [M[1], M[2]] : [navigator.appName, navigator.appVersion, '-?'];
  if ((tem = ua.match(/version\/(\d+)/i)) != null) M.splice(1, 1, tem[1]);
  return M.join(' ');
})();

console.log(navigator.sayswho); // outputs: `Chrome 62`
Copy after login

This function identifies and logs the browser version, which can be utilized for testing or logging purposes, enabling you to distinguish between different browser versions.

The above is the detailed content of How Can I Detect Firefox Versions 3 or 4 Using JavaScript?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template