How to Call C Member Function Pointers?

C Call Pointer To Member Function

Calling pointers to member functions in C requires a unique syntax due to their non-static nature. To invoke such functions effectively, a this pointer representing the object on which the function will be called must be supplied alongside the named parameters.

To specify member function pointers in your code:

typedef void (Box::*HitTest) (int x, int y, int w, int h);

This defines a member function pointer type for the HitTest method of the Box class.

To add member functions to a list:

std::list<HitTest> list;

for (std::list<Box*>::const_iterator i = boxList.begin(); i != boxList.end(); ++i)
{
    Box * box = *i;
    list.push_back(&amp;box->HitTest);
}

To call a pointer to member function:

(box->*h)(xPos, yPos, width, height);

In this example, box represents the this pointer, h is the pointer to the HitTest method, and xPos, yPos, width, and height are the function parameters.

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