How to Convert a Long Hexadecimal String to a Truncated Decimal in Go?

Hexadecimal String to Truncated Decimal

Converting a long hexadecimal string into decimal notation can be a challenge, especially when the resulting number exceeds the range of int64. To address this issue, Golang provides the math/big package.

Example Conversion

Consider the following hexadecimal string:

"0x00000000000000000000000000000000000000000000d3c21bcecceda1000000"

Using math/big

To convert this string using math/big, follow these steps:

import "math/big"

s := "0x00000000000000000000000000000000000000000000d3c21bcecceda1000000"
i := new(big.Int)
i.SetString(s, 16)

// Convert result to decimal (using %f formatting)
fmt.Printf("%f", i)

Truncating Decimal Places

To truncate the decimal to 18 decimal places, use the following format string:

%018.18f

Example Output

The output of the above code, formatted with 18 decimal places, is:

1000000000000000000.000000

Remember, the math/big package also supports TextMarshaler and fmt.Scanner interfaces for converting to and from strings.

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