How to Encapsulate PHP JSON Output in an 'item' Object?

Creating JSON Objects from PHP Arrays: Encapsulating in "item"

In PHP, you can create a JSON object from an array using the json_encode() function. However, by default, the JSON output will not be encapsulated in an object with "item" as its attribute. This article explains how to encapsulate the JSON code in "item": {...}.

The code you provided encodes a PHP array into JSON:

$post_data = json_encode($post_data);

To encapsulate the JSON in an object, you can wrap it in an array with the key "item":

$post_data = json_encode(array('item' => $post_data));

This will output JSON in the following format:

{
  "item": {
    "item_type_id": 4,
    "string_key": "key",
    "string_value": "value",
    "string_extra": "100000583627394",
    "is_public": true,
    "is_public_for_contacts": false
  }
}

However, the JSON output will include brackets "[]" around "item". To ensure that the JSON is output as an object (indicated by "{}" brackets), you can pass the JSON_FORCE_OBJECT constant to json_encode():

$post_data = json_encode(array('item' => $post_data), JSON_FORCE_OBJECT);

This will produce the desired JSON output:

{
  "item": {
    "item_type_id": 4,
    "string_key": "key",
    "string_value": "value",
    "string_extra": "100000583627394",
    "is_public": true,
    "is_public_for_contacts": false
  }
}

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