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Why Does My Async Function Return `Promise { }` Instead of the Expected Value?

Linda Hamilton
Release: 2024-12-09 22:03:12
Original
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Why Does My Async Function Return `Promise {  }` Instead of the Expected Value?

Why Does My Asynchronous Function Return Promise { <pending> } Instead of a Value?

Problem:

In the provided code:

let AuthUser = data => {
  return google.login(data.username, data.password).then(token => { return token } )
}
Copy after login

When executing the following:

let userToken = AuthUser(data)
console.log(userToken)
Copy after login

The output is:

Promise { <pending> }
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Explanation:

Promises in JavaScript are used to represent asynchronous operations. If an asynchronous function returns a promise that is still unresolved, it will log as "pending" when printed.

To capture the result of an asynchronous call, you must use the .then method on the promise. This method takes a callback function as an argument, which will be executed when the promise is resolved.

Solution:

To correctly log the token from the asynchronous function, modify the code as follows:

let AuthUser = function(data) {
  return google.login(data.username, data.password).then(token => { return token } )
}

let userToken = AuthUser(data)
console.log(userToken) // Promise { <pending> }

userToken.then(function(result) {
   console.log(result) // "Some User token"
})
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By using .then, you can handle the result of the promise regardless of whether it is resolved or still pending.

Details:

Promises only resolve once, and the resolved value is passed to .then or .catch methods. The Promises/A spec states that if the function in the .then handler returns a value, the promise resolves with that value. If the handler returns another promise, the original promise resolves with the resolved value of the chained promise.

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