Home > Backend Development > Python Tutorial > Why Does `json.loads()` Throw a 'JSONDecodeError: Expecting Value' and How Can I Fix It?

Why Does `json.loads()` Throw a 'JSONDecodeError: Expecting Value' and How Can I Fix It?

Patricia Arquette
Release: 2024-12-08 06:02:10
Original
590 people have browsed it

Why Does `json.loads()` Throw a

JSONDecodeError: Expecting Value in Python

When attempting to parse JSON using the json.loads() function, an error message like "Expecting value: line 1 column 1 (char 0)" can arise. This error indicates that the input string provided does not conform to the expected JSON format.

Resolving the Issue

The most common cause of this error is an empty or incomplete response body. To resolve it, ensure that the following steps are followed:

  1. Verify that the API call results in a non-empty response. An HTTP response status code in the 200 range should be returned.
  2. Decode the response body using the UTF-8 encoding instead of Unicode. The json.loads() function can handle UTF-8-encoded data directly.
  3. Consider using alternative libraries such as requests or httpx, which provide more user-friendly APIs and built-in JSON support.

Here is an example using the Requests package:

import requests

response = requests.get(url)
if response.status_code != 204:
    return response.json()
Copy after login

To safeguard against violations of HTTP standards, check the Content-Type header to verify that the server intended to deliver JSON. If a ValueError occurs while parsing the JSON, appropriate error handling can be implemented:

if (
    response.status_code != 204 and
    response.headers["content-type"].strip().startswith("application/json")
):
    try:
        return response.json()
    except ValueError:
        # Handle server misbehavior
Copy after login

The above is the detailed content of Why Does `json.loads()` Throw a 'JSONDecodeError: Expecting Value' and How Can I Fix It?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template