Calling Subclass Methods from a Superclass: Understanding Type Compatibility
When working with inheritance in object-oriented programming, accessing methods specific to subclasses from a superclass variable can be challenging. This is because, by default, a variable declared as a superclass type can only access public methods and member variables that exist in the superclass.
To illustrate this, consider the code example provided in the question. Here, a superclass Pet is defined with common properties and methods like name and age. Three subclasses, Dog, Cat, and Bird, inherit from Pet and introduce unique traits and methods for each type of animal.
Within the Kennel main class, the user attempts to access the subclass-specific methods, such as cat.getColor(), dog.getBreed(), and bird.getWingspan(), which are unique to Cat, Dog, and Bird, respectively. However, these methods are not accessible because cat, dog, and bird are declared as instances of the superclass Pet.
To resolve this issue, there are two options:
Declare Variables as Concrete Subclass Types:
Declare variables as specific instances of the subclass. For example:
Cat cat = new Cat("Feline", 12, "Orange"); Dog dog = new Dog("Spot", 14, "Dalmation"); Bird bird = new Bird("Feathers", 56, 12);
Cast Variables to Concrete Subclass Types:
Cast a superclass variable to the expected subclass type using the cast operator ((())). For example:
Pet pet = new Cat("Feline", 12, "Orange"); Cat cat = (Cat) pet;
Both approaches allow access to subclass-specific methods and properties through the respective variables.
In Java, the type of a variable determines the available methods and member variables that can be accessed. By declaring variables as concrete subclasses or casting them to expected subclass types, you ensure access to the desired functionality.
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