Addressing "Cannot execute queries while other unbuffered queries are active" Error with MySQL
Introduction:
MySQL's client protocol imposes a limitation where only one query can be in execution concurrently. When attempting to execute additional queries while results from previous queries remain unfetched, users may encounter the error "Cannot execute queries while other unbuffered queries are active." This issue can arise in specific scenarios, particularly when PHP Data Objects (PDO) is used with the PDO::ATTR_EMULATE_PREPARES attribute set to false.
Cause:
The root cause lies in the MySQL client protocol's inability to have multiple queries in progress simultaneously. Once a query is executed, the client library automatically fetches all its results and caches them, enabling subsequent fetches to iterate over the stored results without communicating with MySQL. This approach, known as "buffered queries," frees the MySQL server from further processing once the initial results are retrieved.
Conversely, unbuffered queries do not cache results, requiring the client to fetch them one at a time. This constraint arises when a second query is executed before the results of the first query have been fully fetched. The MySQL server interprets this as a conflict between active queries and triggers the error message.
Resolution:
To resolve this issue, the following strategies can be employed:
Additional Considerations:
Code Example:
The provided code can be modified to prevent the error by utilizing fetchAll() or explicitly setting PDO::MYSQL_ATTR_USE_BUFFERED_QUERY to true.
$sql ='SELECT temp_id FROM temp1'; $stmt2 = db::db()->prepare($sql); $stmt2->execute(); $rs2 = $stmt2->fetchAll(PDO::FETCH_ASSOC); $stmt2->closeCursor(); $sql='SELECT COUNT(*) AS valid FROM cities_has_zipcodes WHERE cities_id=:cities_id AND zipcodes_id=:zipcodes_id'; $stmt1 = db::db()->prepare($sql); foreach($data AS $row) { try { $stmt1->execute($row); $rs1 = $stmt1->fetchAll(PDO::FETCH_ASSOC); $stmt1->closeCursor(); syslog(LOG_INFO,'$rs1: '.print_r($rs1[0],1).' '.rand()); syslog(LOG_INFO,'$rs2: '.print_r($rs2[0],1).' '.rand()); } catch(PDOException $e){echo(sql_error($e));} }
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