Does Calling pthread_cond_signal Without Mutex Compromise Signaling?
Some literature suggests that calling pthread_cond_signal requires locking the mutex beforehand and unlocking it afterward. However, can you call pthread_cond_signal or pthread_cond_broadcast without mutex locking?
Answer:
No, it is unsafe to call pthread_cond_signal or pthread_cond_broadcast without locking the mutex first. This is illustrated through a simple example involving two processes (A and B).
Process A:
pthread_mutex_lock(&mutex); while (condition == FALSE) pthread_cond_wait(&cond, &mutex); pthread_mutex_unlock(&mutex);
Process B (Incorrect):
condition = TRUE; pthread_cond_signal(&cond);
If condition starts as FALSE and Process B attempts to signal without mutex locking, it is possible for Process A to miss the wake-up signal due to an interleaving of instructions.
Process B (Correct):
pthread_mutex_lock(&mutex); condition = TRUE; pthread_cond_signal(&cond); pthread_mutex_unlock(&mutex);
Locking the mutex in Process B prevents this issue, ensuring Process A receives the wake-up signal.
Note: While it is technically possible to move pthread_cond_signal() after pthread_mutex_unlock(), it is not recommended as it reduces thread scheduling efficiency.
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