How to Explicitly Specialize Member Functions in Class Templates?

Explicit Specialization of Member Functions for Class Templates

Explicit specialization of a member function in a class template requires the surrounding class template to be explicitly specialized as well. The original code in the question attempts to specialize the get_as() member function for double within the context of the X class, but this is incorrect due to the surrounding class template being defined as a template.

To resolve this issue, one can explicitly specialize both the class template and the member function, as seen below:

template <>
template <>
void X<int>::get_as<double>()
{

}

This approach specializes the get_as member function specifically for the X class, while leaving the surrounding class template unspecialized.

If the surrounding class template is to remain unspecialized, alternative techniques can be employed. One such method involves using overloads, as illustrated:

template <class C> class X
{
   template<typename T> struct type { };

public:
   template <class T> void get_as() {
     get_as(type<T>());
   }

private:
   template<typename T> void get_as(type<T>) {

   }

   void get_as(type<double>) {

   }
};

In this approach, the get_as() function is overloaded with two versions: one that takes a generic argument and another that specifically handles the case for double. This allows for explicit specialization of the member function without requiring specialization of the surrounding class template.

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