Why Does My MySQL `mysql_fetch_array()` Only Return the First Row?

Understanding Single-Row Retrieval in MySQL Interactions

In your provided code, you're utilizing the mysql_query() function to retrieve a result set from a MySQL database and subsequently attempt to fetch rows using mysql_fetch_array(). However, you're encountering an issue where only the first row is accessible.

The mysql_fetch_array() function retrieves a row from the result set and represents it as an indexed array. In your case, each row corresponds to a set of matching artist names that begin with "a," "b," or "c."

When you execute mysql_fetch_array() the first time, it places the first row of the result set into the $array_result variable, making $array_result[0] available. However, the subsequent calls to mysql_fetch_array() without specifying a parameter will always return the first row, overwriting previous results.

To fetch multiple rows from the result set, you need to repeat the mysql_fetch_array() function within a loop. For instance, you could use a while or foreach loop to iterate through the result set, calling mysql_fetch_array() within each iteration and storing the resulting array in a variable. This will allow you to access each row individually and echo its contents as desired.

Here's an example using a while loop:

$array = mysql_query("SELECT artist FROM directory WHERE artist LIKE 'a%' OR artist LIKE 'b%' OR artist LIKE 'c%'");
while($row = mysql_fetch_array($array)) {
  var_dump($row); // Outputs contents of each row
}

This loop will iterate through the result set and output the contents of each row, allowing you to access and echo all the available data from the query.

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