Erasing an Element from a List Using a Reverse Iterator
It is possible to encounter a scenario where you wish to remove an element from a list using a reverse iterator, but the erase() function only accepts a regular iterator. This can pose a challenge, as converting a reverse iterator to a regular iterator is not straightforward.
Solution:
The key to resolving this issue lies in understanding the relationship between a reverse iterator and its base iterator. According to the C Standard, the base iterator of a reverse iterator i is &*(i - 1). This means that to obtain the base iterator, we decrement i.
Example:
Consider the following code snippet:
for ( std::list< Cursor::Enum & >::reverse_iterator i = m_CursorStack.rbegin(); i != m_CursorStack.rend(); ++i ) { if ( *i == pCursor ) { m_CursorStack.erase( --(i.base()) ); break; } }
In this example, the base iterator is obtained by decrementing i.base(). By passing this base iterator to the erase() function, we can successfully remove the desired element from the list.
C 11 Solutions:
For C 11 and later, two additional solutions are available:
m_CursorStack.erase( std::next(i).base() );
This solution remains unchanged, while std::next() is used to advance the reverse iterator one position forward, effectively retrieving its base iterator.
std::advance(i, 1); m_CursorStack.erase( i.base() );
In this solution, the reverse iterator is advanced one position using std::advance(), which effectively aligns its base iterator with the desired element for erasure.
Whichever solution you choose, these approaches provide clean and straightforward methods for erasing elements from a list using a reverse iterator.
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