How Can I Pass Arrays by Reference in C ?

Passing Arrays by Reference in C

Passing arrays by reference in C can be achieved by using the appropriate syntax. The code snippet provided in the question raises a compiler error because the syntax is incorrect.

The correct way to pass an array by reference is to use the following format:

void foo(double(&&bar)[10]);

This syntax indicates that bar is a reference to an array of 10 double elements. Passing an array by reference allows the method foo to modify the elements of the array and return them to the caller.

However, this approach has a limitation: it restricts the caller to passing arrays with exactly 10 elements. To overcome this, you can use a templated function:

template<typename T, size_t N>
void foo(T(&&bar)[N]);

This template captures the size of the array at compile time, allowing the caller to pass arrays of any size.

Alternatively, you could use std::vector, which provides a more flexible way to pass and modify arrays of arbitrary size. In C 11 and later, you can also use std::array for fixed-size arrays.

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