How to Check a Bit\'s Status Without Bit Shifting in C and C ?

Checking Bit Status Without Bit Shifting

Consider the following scenario:

<br>int temp = 0x5E; // in binary 0b1011110.<br>

Suppose you want to determine if bit 3 in temp is 1 or 0, without resorting to bit shifting and masking. Is there a built-in function for this task, or must you implement your own solution?

In C, you can conceal bit manipulation by creating a macro:

#define CHECK_BIT(var,pos) ((var) &amp; (1<<(pos)))

Using this macro, you can check the n^th bit from the right end using the following syntax:

CHECK_BIT(temp, n - 1)

In C , you have the option of utilizing std::bitset. This class offers a way to manipulate bits without explicit bit shifting or masking. You can access individual bits in a bitset using the at() method, for instance:

std::bitset<8> temp_bitset(temp);
if (temp_bitset.at(2)) { // bit 3
    // Bit 3 is set
}

By utilizing these techniques, you can conveniently check bit status without the need for manual bit manipulation, ensuring clarity and maintainability in your code.

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