Executing Binaries from Memory Without Disk Writeback
In your program, you have embedded a binary within a variable and are seeking a way to execute it without disk writeback. This involves finding a mechanism to execute the binary directly from memory.
C/C Approach (Using mprotect() System Call)
Using C or C (via CGO in Go), you can leverage the mprotect() system call in Linux to manipulate memory protection. This call allows you to change the permissions of a memory region, making it executable. Once the region is protected as executable, you can execute it by jumping into it.
#include <sys/mman.h> int main() { // ... (Load binary into memory) // Change memory protection to executable mprotect(binary_buffer, binary_size, PROT_READ | PROT_WRITE | PROT_EXEC); // Jump into the executable region ((void (*)(void))binary_buffer)(); }
Go Approach (Assembly Techniques)
In Go, there are no direct system calls that allow you to specify memory protection. However, you can use assembly techniques to manipulate the memory protection using the syscall.Syscall function to invoke the mprotect() system call from Go code.
import ( "syscall" "unsafe" ) // ... (Load binary into memory) // Change memory protection to executable syscall.Syscall(syscall.SYS_MPROTECT, uintptr(unsafe.Pointer(&binary_buffer[0])), uintptr(binary_size), syscall.PROT_READ|syscall.PROT_WRITE|syscall.PROT_EXEC) // Jump into the executable region (((func()) unsafe.Pointer(&binary_buffer[0])))()
Note:
The above is the detailed content of How Can I Execute a Binary from Memory Without Writing to Disk?. For more information, please follow other related articles on the PHP Chinese website!