gob: Encoding Maps with Interfaces
When attempting to encode a map[string]interface{} using Gob, users may encounter the error message: "gob: type not registered for interface: map[string]interface {}." This error occurs because Gob requires that the type of the data being encoded be registered before it can be processed.
The solution to this problem is straightforward: register the type with Gob using the gob.Register function. In this case, the following code should be added to the program:
gob.Register(map[string]interface{}{})
This registration step informs Gob that it should be able to encode and decode maps with string keys and interface values.
To demonstrate this, consider the following revised code:
package main import ( "bytes" "encoding/gob" "encoding/json" "fmt" "log" ) func CloneObject(a, b interface{}) []byte { gob.Register(map[string]interface{}{}) buff := new(bytes.Buffer) enc := gob.NewEncoder(buff) dec := gob.NewDecoder(buff) err := enc.Encode(a) if err != nil { log.Panic("e1: ", err) } b1 := buff.Bytes() err = dec.Decode(b) if err != nil { log.Panic("e2: ", err) } return b1 } func main() { var a interface{} a = map[string]interface{}{"X": 1} b2, err := json.Marshal(&a) fmt.Println(string(b2), err) var b interface{} b1 := CloneObject(&a, &b) fmt.Println(string(b1)) }
Now, when this code is run, the Gob encoder will successfully encode the map[string]interface{} into a byte array. The error message will no longer be displayed.
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