How to Convert Hexadecimal Strings to Byte Arrays in Go?

Transferring Hexadecimal Strings to Byte Arrays in Go

Converting hexadecimal strings to byte arrays in Go is a common task in various programming scenarios. This article demonstrates a straightforward method to achieve this using the hex.DecodeString() function.

The problem at hand is to convert the hexadecimal string "46447381" into a byte array representing the individual hexadecimal values: {0x46, 0x44, 0x73, 0x81}.

The solution to this problem lies in leveraging the hex.DecodeString() function:

package main

import (
    "encoding/hex"
    "fmt"
)

func main() {
    s := "46447381"

    data, err := hex.DecodeString(s)
    if err != nil {
        panic(err)
    }
    fmt.Printf("% x", data)
}

Explanation:

1. The hex.DecodeString() function takes a hexadecimal string as input and returns a byte slice containing the decoded hexadecimal values.
2. The decoded byte slice, data, is then printed using fmt.Printf("% x", data) to display the values in hexadecimal format.

Output:

46 44 73 81

Note:

It's important to remember that simply printing the byte slice using fmt.Println(data) will output the values in decimal format instead of hexadecimal. Therefore, using fmt.Printf("% x", data) is crucial to display the hexadecimal values accurately.

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