Why Don't Case Ranges Work in C Switch Statements?

How to Use Case Ranges in Switch Statements

When working with switch statements in C , you may encounter errors when attempting to create ranges of values as cases. This issue occurs because case ranges are not part of the standard C syntax. Instead, they are an extension supported by certain compilers.

In the provided code:

switch(score){
    case >= 100:
        cout << "a";
        break;
    case >= 50:
        cout << "b";
        break;
    ...
}

The compiler is unable to parse the code correctly due to the use of >= and ==. To fix this problem, you can do one of the following:

1. Use a compiler that supports case ranges as an extension. Some compilers that support this feature include GCC, Clang, and Intel C/C Compiler.
2. Replace the case ranges with individual cases. For example, the following code will compile correctly:

switch(score){
    case 100:
        cout << "a";
        break;
    case 50:
        cout << "b";
        break;
    ...
}

Alternatively, you can consider using a different programming construct, such as an if-else statement, to evaluate the score:

if (score >= 100) {
    cout << "a";
} else if (score >= 50) {
    cout << "b";
} else {
    ...
}

By understanding the limitations of case ranges in C , you can effectively handle values in your switch statements.

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