How to Compile Go Code Without Debugging Information?

Compiling Go Code Without Debugging Information

In Go, debug information is included by default during compilation, which can make it easier to debug code. However, this information can also be extracted to decompile the code. To prevent this, we need to exclude debugging information while compiling.

Using -ldflags

The -ldflags flag can be used to pass options to the linker. To remove symbol table and debugging information, add -s -w to the -ldflags option. Here's an example:

go build -ldflags="-s -w" main.go

Additional Tip for Go 1.13

In Go 1.13 and later, the -trimpath flag can be used to reduce the length of file paths stored in the executable. This can further minimize the size of the generated binary.

Note on gccgo

It's important to note that using gccgo, a Go compiler based on GCC, does not solve the problem. If you compile without the -g flag using gccgo, you will encounter an error related to missing debug information.

Recommendation

For complete removal of debugging information, it is recommended to use the -ldflags="-s -w" option. This effectively strips symbols and debug information, making it harder to decompile the compiled binary.

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