How can you pretty-print `std::tuple` using variadic templates and custom delimiters?-C++-php.cn

How can you pretty-print `std::tuple` using variadic templates and custom delimiters?

Susan Sarandon

Release： 2024-11-08 07:27:01

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How can you pretty-print `std::tuple` using variadic templates and custom delimiters?

Pretty-Printing std::tuple

In a previous question, we created an elegant solution for pretty-printing STL containers. Now, let's tackle pretty-printing for std::tuple using variadic templates.

For std::pair, we can print using custom operators:

std::ostream &operator<<(std::ostream &o, const std::pair<S,T> &p)
{
  return o << "(" << p.first << ", " << p.second << ")";
}

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To generalize this to tuples, we can leverage template argument unpacking and indices generation:

namespace aux{
template<std::size_t... Is> struct seq{}; // dummy helper type

template<std::size_t N, std::size_t... Is>
struct gen_seq : gen_seq<N-1, N-1, Is...>{};

template<std::size_t... Is>
struct gen_seq<0, Is...>: seq<Is...>{};

template<class Ch, class Tr, class Tuple, std::size_t... Is>
void print_tuple(std::basic_ostream<Ch,Tr>& os, Tuple const& t, seq<Is...>){ // overload to print tuples
  using swallow = int[]; // silence unused warning
  (void)swallow{0, (void(os << (Is == 0? "" : ", ") << std::get<Is>(t)), 0)...}; 
}
}

template<class Ch, class Tr, class... Args>
auto operator<<(std::basic_ostream<Ch, Tr>& os, std::tuple<Args...> const& t) -> std::basic_ostream<Ch, Tr>&
{
  os << "(";
  aux::print_tuple(os, t, aux::gen_seq<sizeof...(Args)>()); // call template overload with index helper to print
  return os << ")";
}

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To add custom delimiters (e.g., for char and wchar_t), we can use partial specializations:

// Delimiters for tuple
template<class... Args>
struct delimiters<std::tuple<Args...>, char> {
  static const delimiters_values<char> values;
};

template<class... Args>
const delimiters_values<char> delimiters<std::tuple<Args...>, char>::values = { "(", ", ", ")" };

template<class... Args>
struct delimiters<std::tuple<Args...>, wchar_t> {
  static const delimiters_values<wchar_t> values;
};

template<class... Args>
const delimiters_values<wchar_t> delimiters<std::tuple<Args...>, wchar_t>::values = { L"(", L", ", L")" };

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And adapt the operator<< and print_tuple accordingly:

template<class Ch, class Tr, class... Args>
auto operator<<(std::basic_ostream<Ch, Tr>& os, std::tuple<Args...> const& t) -> std::basic_ostream<Ch, Tr>&
{
  typedef std::tuple<Args...> tuple_t;
  if(delimiters<tuple_t, Ch>::values.prefix != 0)
    os << delimiters<tuple_t,char>::values.prefix;

  print_tuple(os, t, aux::gen_seq<sizeof...(Args)>());

  if(delimiters<tuple_t, Ch>::values.postfix != 0)
    os << delimiters<tuple_t,char>::values.postfix;

  return os;
}

template<class Ch, class Tr, class Tuple, std::size_t... Is>
void print_tuple(std::basic_ostream<Ch, Tr>& os, Tuple const& t, seq<Is...>){ 
  char const* delim = delimiters<Tuple, Ch>::values.delimiter;
  if(!delim) delim = "";
  (void)swallow{0, (void(os << (Is == 0? "" : delim) << std::get<Is>(t)), 0)...};
}

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Now, printing std::tuple with custom delimiters is as simple as:

auto a = std::make_tuple(5, "Hello", -0.1);
std::cout << a << std::endl; // prints: (5, "Hello", -0.1)

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