Why Does My Java Code Throw an 'Integer Number Too Large' Error When Using 600851475143?

Troubleshoot "Integer Number Too Large" Error for 600851475143

Consider the following code snippet:

public class Three {
    public static void main(String[] args) {
        Three obj = new Three();
        obj.function(600851475143);
    }

    private Long function(long i) {
        Stack<Long> stack = new Stack<>();

        for (long j = 2; j <= i; j++) {
            if (i % j == 0) {
                stack.push(j);
            }
        }
        return stack.pop();
    }
}

When this code is executed with the literal 600851475143 passed to function, it throws an "Integer Number Too Large" error. To understand why, we need to delve into the data types involved.

In Java, there are primitive data types, such as int and long, which represent numbers without objects.

• int is a 32-bit signed integer, meaning it can represent integers between -2,147,483,648 and 2,147,483,647.
• long is a 64-bit signed integer, providing a much wider range of values from -9,223,372,036,854,775,808 to 9,223,372,036,854,775,807.

The issue here is that 600851475143 exceeds the maximum value representable by an int. To fix this, we need to use a literal of type long by appending an "L" suffix to the number: 600851475143L.

obj.function(600851475143L);

With this modification, the code will run without encountering the error and will return the largest prime factor of 600851475143L.

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