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Why Doesn't My PHP Code Display Echoes and a Table When Using `if(isset($_POST['submit']))`?

Patricia Arquette
Release: 2024-11-06 16:00:04
Original
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Why Doesn't My PHP Code Display Echoes and a Table When Using `if(isset($_POST['submit']))`?

Why Using if(isset($_POST['submit'])) Does Not Display Echoes and Table

In PHP scripting, if(isset($_POST['submit'])) is commonly used to conditionally display content based on whether a form has been submitted. However, this technique is not working in your code because the submit button lacks a proper name attribute.

Understanding the if(isset()) Function

The if(isset()) function checks if a specific variable is set, meaning it has been declared and initialized. In your case, if(isset($_POST['submit'])) checks if the variable $_POST['submit'] exists.

Missing Name Attribute in Submit Button

The problem arises because your submit button does not have a name attribute, as shown here:

<p><input type="submit" value="Submit" /></p>
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Without a name attribute, the submitted form data will not include a $_POST['submit'] variable, making the if(isset($_POST['submit'])) condition always false.

How to Fix the Issue

To fix this, simply add a name attribute to your submit button with a unique value, like so:

<p><input type="submit" value="Submit" name="submit" /></p>
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This will create the necessary $_POST['submit'] variable when the form is submitted.

With this fix, your code will display the echoes and table only when the "Submit" button is clicked, as now if(isset($_POST['submit'])) will evaluate to true when the form is submitted.

...
<p><input type="submit" value="Submit" name="submit" /></p>

if(isset($_POST['submit'])){
    // Display echoes and table
}
....
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