Why Does My PHP Code Return 1970-01-01 When Converting dd/mm/yyyy Dates in URLs?

Converting Dates in URLs from dd/mm/yyyy to YYYY-MM-DD

In PHP, you have provided code that attempts to convert a date in the format dd/mm/yyyy to the YYYY-MM-DD format. However, you have encountered an issue where the conversion is returning an unexpected value of 1970-01-01.

Problem with strtotime()

The problem lies in the use of the PHP strtotime() function. When parsing a date in the dd/mm/yyyy format, strtotime() assumes that the first two digits represent the month (mm), and the next two digits represent the day (dd). For example, 20/02/2000 would be interpreted as February 20, 2000.

However, in your case, the date in the URL is in a day/month/year format (dd/mm/yyyy). This means that the first two digits represent the day, and the next two digits represent the month. As a result, strtotime() misinterprets the date and returns an incorrect value.

Solution Using DateTime::createFromFormat()

To resolve this issue, it is recommended to use the DateTime::createFromFormat() method instead of strtotime(). This method allows you to specify the exact format of the date string, ensuring that it is parsed correctly. Here's an updated version of your code:

<code class="php">$date = $date1 = DateTime::createFromFormat('d/m/Y', '20/02/2000');
$D->query = $date->format('Y-m-d'); // 2000-02-20</code>

By using DateTime::createFromFormat(), you can accurately convert the date in the URL to the YYYY-MM-DD format.

Additional Considerations

To prevent similar issues in the future, it's important to correctly format dates in URLs. If you are passing dates in the dd/mm/yyyy format, ensure that the first two digits represent the day, and the next two digits represent the month. Alternatively, consider using a more standardized format such as YYYY-MM-DD.

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