How to Update a Feedback Display with AJAX Every 10 Seconds in jQuery?-PHP Tutorial-php.cn

How to Update a Feedback Display with AJAX Every 10 Seconds in jQuery?

Linda Hamilton

Release： 2024-11-04 01:54:02

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How to Update a Feedback Display with AJAX Every 10 Seconds in jQuery?

jQuery: Updating Feedback Display via AJAX Every 10 Seconds

A scenario arises where you want to update a feedback div every 10 seconds using AJAX. To achieve this, you may use the following jQuery and PHP codes.

jQuery Script:

<code class="javascript">$(document).ready(function(){
  setInterval(get_fb, 10000);
});

function get_fb(){
  var feedback = $.ajax({
    type: "POST",
    url: "feedback.php",
    async: false
  }).responseText;

  $('div.feedback-box').html(feedback);
}</code>

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PHP Script:

<code class="php">$result = mysql_query("SELECT * FROM feedback ORDER BY RAND() LIMIT 0,1");
while($row = mysql_fetch_array($result))
{
  $name = $row['name'];
  $location = $row['location'];
  $feedback = $row['feedback'];

  echo "
    <p>Name: $name, Location: $location, Feedback: $feedback.</p>
    ";
} </code>

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Explanation:

This code employs the setInterval() function to call the get_fb() function every 10 seconds. The get_fb() function uses an AJAX request to retrieve feedback data from a database and updates the content of the div with the retrieved feedback.

Alternative Option:

If you want to run the get_fb() function only after the AJAX call is successful, you can use the .ajax().success() callback:

<code class="javascript">function get_fb(){
  var feedback = $.ajax({
    type: "POST",
    url: "feedback.php",
    async: false
  }).success(function(){
    setTimeout(function(){get_fb();}, 10000);
  }).responseText;

  $('div.feedback-box').html(feedback);
}</code>

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