How to Efficiently Remove Strings from Slices in Go?

Deleting Elements from String Slices in Go

In Go, a slice of strings can be a valuable data structure for managing collections of text. However, at times, it becomes necessary to remove specific strings from these slices. This article addresses the common challenge of removing strings from slices in Go.

Finding and Deleting a Specific String

To remove a string from a slice, we need to first identify its position using linear search. We iterate through the slice, comparing each element with the string we intend to remove. Once found, the string can be removed using slice tricks, as demonstrated below:

<code class="go">for i, v := range strings {
    if v == "two" {
        strings = append(strings[:i], strings[i+1:]...)
        break
    }
}</code>

An alternative slice trick that achieves the same result is:

<code class="go">for i, v := range strings {
    if v == "two" {
        strings = strings[:i+copy(strings[i:], strings[i+1:])]
        break
    }
}</code>

Example Implementation

Using the technique described above, the following code snippet demonstrates the removal of the string "two" from the slice:

<code class="go">strings := []string{"one", "two", "three"}
for i, v := range strings {
    if v == "two" {
        strings = append(strings[:i], strings[i+1:]...)
        break
    }
}
fmt.Println(strings) // Output: [one three]</code>

Wrapper Function

To simplify the process further, we can wrap the removal operation into a function:

<code class="go">func remove(s []string, r string) []string {
    for i, v := range s {
        if v == r {
            return append(s[:i], s[i+1:]...)
        }
    }
    return s
}</code>

Using this function:

<code class="go">s := []string{"one", "two", "three"}
s = remove(s, "two")
fmt.Println(s) // Output: [one three]</code>

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