Why Am I Getting \'The Specified Child Already Has a Parent\' Error in Android?-javaTutorial-php.cn

Why Am I Getting \'The Specified Child Already Has a Parent\' Error in Android?

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Release： 2024-10-30 13:51:27

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Why Am I Getting

Error: The Specified Child Already Has a Parent (Android)

Problem:

Frequently switching between two layouts results in the following error:

FATAL EXCEPTION: main
java.lang.IllegalStateException: The specified child already has a parent. You must call removeView() on the child's parent first.

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Code Snippet:

<code class="java">tv = new TextView(getApplicationContext()); // initialized elsewhere
et = new EditText(getApplicationContext()); // initialized elsewhere

private void ConsoleWindow() {
    runOnUiThread(new Runnable() {
        @Override
        public void run() {
            // MY LAYOUT:
            setContentView(R.layout.activity_console);
            // LINEAR LAYOUT
            LinearLayout layout = new LinearLayout(getApplicationContext());
            layout.setOrientation(LinearLayout.VERTICAL);
            setContentView(layout);

            // TEXTVIEW
            layout.addView(tv); // ERROR IN THIS LINE DURING 2ND RUN
            // EDITTEXT
            et.setHint("Enter Command");
            layout.addView(et);
        }
    });
}</code>

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Solution:

The error message suggests removing the child (TextView) from its current parent before adding it to the new layout.

Add the following code before layout.addView(tv);:

<code class="java">if (tv.getParent() != null) {
    ((ViewGroup) tv.getParent()).removeView(tv); // Fix
}</code>

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This ensures that the TextView is properly removed from any existing parent before being added to the new layout, preventing the specified parent conflict.

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