Home > Backend Development > Python Tutorial > How to Retrieve Files from Subfolders Recursively in Python?

How to Retrieve Files from Subfolders Recursively in Python?

Linda Hamilton
Release: 2024-10-29 23:13:29
Original
241 people have browsed it

How to Retrieve Files from Subfolders Recursively in Python?

Retrieving Files from Subfolders Recursively

Problem Statement

A Python script is encountered with a problem while recursively searching subfolders for files with a specific extension. The script aims to create a list of the found files, but the subfolders retrieved by the script are in a list rather than representing the folder containing the located file.

Solution

To resolve this issue, the dirpath, represented by the "root" variable in the provided code, should be utilized instead of the subFolder variable. The dirpath contains the absolute path of the directory where the located file resides.

Code Snippet

The following revised Python code demonstrates the correct usage of the dirpath:

<code class="python">import os
result = [os.path.join(dp, f) for dp, dn, filenames in os.walk(PATH) for f in filenames if os.path.splitext(f)[1] == '.txt']</code>
Copy after login

By employing this modification, the code will effectively traverse subfolders recursively and create a list of files with the desired extension, with each file path including the folder it belongs to.

Additional Options

In addition to the primary solution, alternative approaches using the glob module or Python's built-in pathlib module for Python 3.4 and above are also provided to offer a more comprehensive range of options.

Conclusion

This modified script accurately identifies and lists files with the specified extension within specified folders and their subfolders, providing a robust solution for recursive file searching in Python.

The above is the detailed content of How to Retrieve Files from Subfolders Recursively in Python?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template