Home > Web Front-end > JS Tutorial > How to Exclude the Sender When Broadcasting Messages with Socket.IO?

How to Exclude the Sender When Broadcasting Messages with Socket.IO?

Barbara Streisand
Release: 2024-10-27 08:10:30
Original
971 people have browsed it

How to Exclude the Sender When Broadcasting Messages with Socket.IO?

How to Send Responses to All Clients Except the Sender in Socket.IO

To send messages to all connected clients in Socket.IO, you typically use the io.sockets.emit() method. However, you may encounter situations where you need to selectively broadcast messages to all clients except the sender.

To achieve this, you can utilize the socket.broadcast.emit() method provided by Socket.IO. This method allows you to send messages to all connected clients apart from the one that initiated the request.

Consider the following snippet:

<code class="javascript">socket.broadcast.emit('message', "this is a test");</code>
Copy after login

In this example, the message with the text "this is a test" will be sent to all connected clients except the one that sent the message.

You can also use the broadcast property without specifying a specific event name, which will broadcast any emitted event to all clients except the sender. For instance:

<code class="javascript">socket.broadcast.emit({ event: 'message', data: "this is a test" });</code>
Copy after login

This alternative approach allows you to specify additional data along with the event name in the message.

By employing this technique, you can effectively broadcast messages to all connected clients while excluding the originating sender, enabling you to implement interactive and targeted communication mechanisms in your Socket.IO application.

The above is the detailed content of How to Exclude the Sender When Broadcasting Messages with Socket.IO?. For more information, please follow other related articles on the PHP Chinese website!

source:php.cn
Statement of this Website
The content of this article is voluntarily contributed by netizens, and the copyright belongs to the original author. This site does not assume corresponding legal responsibility. If you find any content suspected of plagiarism or infringement, please contact admin@php.cn
Latest Articles by Author
Popular Tutorials
More>
Latest Downloads
More>
Web Effects
Website Source Code
Website Materials
Front End Template