How to Construct a Multi-Level Dictionary with Variable Depth Given a Nested List?

Constructing a Multi-Level Dictionary with Varying Depth

Question:

How can one construct a multi-level dictionary with a variable depth, given a list of nested values? Consider the following sample list:

<code>[A][B1][C1] = 1
[A][B1][C2] = 2
[A][B2] = 3
[D][E][F][G] = 4</code>

The desired output is a multi-level dictionary resembling the following structure:

<code>A
--B1
-----C1 = 1
-----C2 = 1
--B2 = 3
D
--E
----F
------G = 4</code>

Solution:

Using the defaultdict from the collections module, one can dynamically create nested dictionaries without the need for hardcoding insertion statements. The defaultdict returns a default value when an existing key is not found. Here's how it can be implemented:

<code class="python">from collections import defaultdict

# Define a function to create a nested dictionary with any level of depth
nested_dict = lambda: defaultdict(nested_dict)

# Create the nested dictionary using the nested_dict function
nest = nested_dict()

# Populate the nested dictionary with the given data
nest[0][1][2][3][4][5] = 6

print(nest)</code>

This code will create a nested dictionary with a depth of 7, where the value for the key [0][1][2][3][4][5] is set to 6. The nested dictionary can be accessed using the same key structure, allowing for dynamic creation and retrieval of data at various levels.

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