jquery - 实现修改的功能，用ajax怎么实现，就是一个edit.php读出数据,update.php更新数据，怎么实现？

<code class="lang-js">$.ajax({
  type:'post',
  url:'edit.php',
  success:function(data){
    $(result).html(JSON.parse(data));
  }
})
</code>

<code class="lang-php">// 摘自自己去年年初写的页面TAT大牛请轻喷
<?php include("common/conn.php");//链接数据库
$type=htmlspecialchars($_POST['type']);
$uid=$_SESSION['uid'];
$content=htmlspecialchars($_POST['content']);
$content=mysql_escape_string($content);
$create_time=date("Y-m-d H:i:s");
$checkstate='1';
$query="INSERT INTO f_post(type,uid,content,create_time,checkstate) 
    VALUES('$type','$uid','$content','$create_time','$checkstate')";
$queryId="SELECT P.`id` FROM `f_post` P WHERE `uid`=".$uid." ORDER BY P.`id` DESC LIMIT 1";

if($mysqli->query($query)===TRUE){
    if($pids=$mysqli->query($queryId))
    {
        while($id=$pids->fetch_object())
        {
            $pid=$id->id;
        }   
    }
    $result = array(
        'id'=>$pid,
        'type'=>$type,
        'uid'=>$uid,
        'content'=>$content,
        'create_time'=>date("H:i:s Y-m-d",strtotime($create_time)),
        'editable'=>true
    );
    echo json_encode($result);
}
else
    exit();
</code>

<code>$('submit_btn').click(function(){
    $.post('http://www.example.com/update.php',{data:data},function(callback)
{

})
})
</code>