Wie kann man in der Baidu Map API mit Java Standortkoordinaten basierend auf der Adresse suchen und anzeigen?

import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.HttpURLConnection;
import java.net.URL;

import org.json.JSONArray;
import org.json.JSONObject;

public class MapSearchDemo {

    public static void main(String[] args) {
        String address = "北京市海淀区中关村";
        String ak = "your_baidu_map_ak";

        try {
            // 构建URL
            String urlString = "http://api.map.baidu.com/geocoding/v3/?address=" + address + "&output=json&ak=" + ak;
            URL url = new URL(urlString);

            // 发起HTTP请求
            HttpURLConnection connection = (HttpURLConnection) url.openConnection();
            connection.setRequestMethod("GET");

            BufferedReader reader = new BufferedReader(new InputStreamReader(connection.getInputStream()));
            StringBuilder response = new StringBuilder();
            String line;
            while ((line = reader.readLine()) != null) {
                response.append(line);
            }
            reader.close();

            // 解析JSON数据
            JSONObject jsonObject = new JSONObject(response.toString());
            int status = jsonObject.getInt("status");
            if (status == 0) {
                JSONArray results = jsonObject.getJSONArray("result");
                if (results.length() > 0) {
                    JSONObject location = results.getJSONObject(0).getJSONObject("location");

                    // 提取经纬度
                    double lng = location.getDouble("lng");
                    double lat = location.getDouble("lat");

                    System.out.println("地址：" + address);
                    System.out.println("经度：" + lng);
                    System.out.println("纬度：" + lat);
                } else {
                    System.out.println("未找到相关地址信息！");
                }
            } else {
                System.out.println("请求失败，错误码：" + status);
            }
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}