表 1 中的列列表： Plan_ID、Claim_id、Patient_id、B_OR_G
表2中的列列表： 奥吉德、沙普兰德
select distinct a.Plan_ID
, a.Total_Claims
, Total_Patients
, b.PERIOD
, b.ORGID,a.B_OR_G
FROM (Select distinct Plan_ID
, count(distinct Claim_id) as Total_Claims
, count(distinct Patient_id) as Total_Patients
from table1 group by 1) a
JOIN (select *
, row_number() over (partition by ORGID,SHAPLANID order by PROCESSINGDATE desc) as rank
from table2 qualify rank = 1) b
ON LTRIM(a.PLAN_ID, '0') = b.SHAPLANID
在上面的查询中，我想从 table1（即 a）中再提取一个名为“B_or_G”的列，但不会干扰 group by 子句，因为根据我们的要求这是必要的。
有没有更好的方法来做到这一点？ 谢谢！！
我认为您可以使用 ANY_VALUE(B_or_G)
举个例子：
select distinct a.Plan_ID , a.Total_Claims , Total_Patients , b.PERIOD , b.ORGID,a.B_OR_G FROM (Select distinct Plan_ID , count(distinct Claim_id) as Total_Claims , count(distinct Patient_id) as Total_Patients , ANY_VALUE(B_OR_G) from table1 group by 1) a JOIN (select * , row_number() over (partition by ORGID,SHAPLANID order by PROCESSINGDATE desc) as rank from table2 qualify rank = 1) b ON LTRIM(a.PLAN_ID, '0') = b.SHAPLANID