我别无选择，只能在处理程序中调用获取器的提交方法。它正在访问路由器中正确的操作方法，但是我无法将该方法传递给操作，即表单中定义的 method='POST 。如何访问处理程序内的fetch.Form方法？
const fetcher = useFetcher()
const handlerLogin = useCallback(async () => {
console.log(fetcher.formMethod) //-> outputting undefined
fetcher.submit({ value: 'social' }, { method: fetcher.formMethod })
},[])
return (
<Card className={styles.loginCard}>
<fetcher.Form method='POST' action='/'>
.............. 
尝试这个解决方案，将方法传递给
handlerLogin函数：const fetcher = useFetcher(); const handlerLogin = useCallback(async (formMethod) => { fetcher.submit({ value: 'social' }, { method: formMethod }); }, []); return (
{/* other parts ... */}
);