<p>嘿，laravel 开发人员，我发现了部分模拟的问题，我需要测试一个使用内部方法的方法，这需要被模拟，我尝试使用几种方法来模拟该方法，例如下一个想法：</p> <pre class="brush:php;toolbar:false;">#1 $mockMyClass = Mockery::mock( $myClassInstance )->makePartial(); #2 $mockMyClass = $this->partialMock(); #3 $mockMyClass = $this->createPartialMock(); // and then $mockMyClass->shouldReceive('internalMethod') ->andReturn($responseInternalMethod);</pre> <p>并且显然使用文档 Laravel Mocking Objects 中描述的方式</p> <pre class="brush:php;toolbar:false;">use App\Service; use Mockery\MockInterface; $mock = $this->partialMock(Service::class, function (MockInterface $mock) { $mock->shouldReceive('process')->once(); });</pre> <p>这些想法都行不通，$mockMyClass 总是执行真正的方法，而不是应该返回 $responseInternalMethod 的模拟方法。有人也有这个问题吗？我需要确认是否是 Laravel、Mockito 或外部的问题，而不是本地环境问题，哈哈。我读懂了你们！</p> <p>技术细节： Laravel 9.x PHP 8.1 PHP 单元 9.5 嘲讽1.5</p>

public function testRealExternalMethod()
{
    // Create a mock of the dependency that will be used by the class
    $mockDependency = $this->createMock(Dependency::class);
    
    // in this case we need to use a partial mock because we have an internal method
    $mockMyClass = Mockery::mock(
        MyClass::class,
        [$mockDependency, $parameter1]
    )
        ->makePartial();

    $responseInternalMethod = ['needed data'];

    $mockMyClass->shouldReceive('internalMethod')
        ->andReturn($responseInternalMethod);

    $result = $mockMyClass->realExternalMethod($parameter2, $parameter3);
}